Given a matrix of M x N elements (M rows, N columns), return all elements of the matrix in diagonal order as shown in the below image.
Input:
[
[ 1, 2, 3 ],
[ 4, 5, 6 ],
[ 7, 8, 9 ]
]
Output: [1,2,4,7,5,3,6,8,9]
Explanation:
The total number of elements of the given matrix will not exceed 10,000.
public class Solution {
public int[] findDiagonalOrder(int[][] matrix) {
if (matrix.length == 0)
return new int[0];
int r = 0, c = 0, m = matrix.length, n = matrix[0].length, arr[] = new int[m * n];
for (int i = 0; i < m * n; i++) {
arr[i] = matrix[r][c];
if ((r + c) % 2 == 0) { // moving up
if (c == n - 1)
r++;
else if (r == 0)
c++;
else {
r--;
c++;
}
} else { // moving down
if (r == m - 1)
c++;
else if (c == 0)
r++;
else {
r++;
c--;
}
}
}
return arr;
}
}