Binary Tree Preorder Traversal
Given a binary tree, return the preorder traversal of its nodes' values.
Example:
Input: [1,null,2,3]
1
\
2
/
3
Output: [1,2,3]
Follow up: Recursive solution is trivial, could you do it iteratively?
class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> ans = new ArrayList<>();
Stack<TreeNode> st = new Stack<>();
if (root == null)
return ans;
st.push(root);
while (st.size() != 0) {
TreeNode curr = st.pop();
ans.add(curr.val);
if (curr.right != null)
st.push(curr.right);
if (curr.left != null)
st.push(curr.left);
}
return ans;
}
}
Last updated