Find Elements in a Contaminated Binary Tree
Last updated
Last updated
Given a binary tree with the following rules:
root.val == 0
If treeNode.val == x
and treeNode.left != null
, then treeNode.left.val == 2 * x + 1
If treeNode.val == x
and treeNode.right != null
, then treeNode.right.val == 2 * x + 2
Now the binary tree is contaminated, which means all treeNode.val
have been changed to -1
.
You need to first recover the binary tree and then implement the FindElements
class:
FindElements(TreeNode* root)
Initializes the object with a contamined binary tree, you need to recover it first.
bool find(int target)
Return if the target
value exists in the recovered binary tree.
Example 1:
Example 2:
Example 3:
Constraints:
TreeNode.val == -1
The height of the binary tree is less than or equal to 20
The total number of nodes is between [1, 10^4]
Total calls of find()
is between [1, 10^4]
0 <= target <= 10^6