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# Maximum Product Subarray

Given an integer array `nums`, find the contiguous subarray within an array (containing at least one number) which has the largest product.

**Example 1:**

```
Input: [2,3,-2,4]
Output: 6
Explanation: [2,3] has the largest product 6.
```

**Example 2:**

```
Input: [-2,0,-1]
Output: 0
Explanation: The result cannot be 2, because [-2,-1] is not a subarray.
```

```java
public class Solution {
    public int maxProduct(int A[]) {
        // store the result that is the max we have found so far
        int r = A[0], n = A.length;
        int imax = A[0], imin = A[0];
        // imax/imin stores the max/min product of
        // subarray that ends with the current number A[i]
        for (int i = 1; i < n; i++) {
            // multiplied by a negative makes big number smaller, small number bigger
            // so we redefine the extremums by swapping them
            if (A[i] < 0) {
                int t = imin;
                imin = imax;
                imax = t;
            }
            // max/min product for the current number is either the current number itself
            // or the max/min by the previous number times the current one
            imax = Math.max(A[i], imax * A[i]);
            imin = Math.min(A[i], imin * A[i]);
            // the newly computed max value is a candidate for our global result
            r = Math.max(r, imax);
        }
        return r;
    }
}
```


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