Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product.
Example 1:
Input: [2,3,-2,4]
Output: 6
Explanation: [2,3] has the largest product 6.
Example 2:
Input: [-2,0,-1]
Output: 0
Explanation: The result cannot be 2, because [-2,-1] is not a subarray.
publicclassSolution {publicintmaxProduct(intA[]) {// store the result that is the max we have found so farint r =A[0], n =A.length;int imax =A[0], imin =A[0];// imax/imin stores the max/min product of// subarray that ends with the current number A[i]for (int i =1; i < n; i++) {// multiplied by a negative makes big number smaller, small number bigger// so we redefine the extremums by swapping themif (A[i] <0) {int t = imin; imin = imax; imax = t; }// max/min product for the current number is either the current number itself// or the max/min by the previous number times the current one imax =Math.max(A[i], imax *A[i]); imin =Math.min(A[i], imin *A[i]);// the newly computed max value is a candidate for our global result r =Math.max(r, imax); }return r; }}