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# Queue Reconstruction by Height

Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers `(h, k)`, where `h` is the height of the person and `k` is the number of people in front of this person who have a height greater than or equal to `h`. Write an algorithm to reconstruct the queue.

**Note:**\
The number of people is less than 1,100. 

**Example**

```
Input:
[[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]]

Output:
[[5,0], [7,0], [5,2], [6,1], [4,4], [7,1]]
```

```java
class Solution {
    public int[][] reconstructQueue(int[][] people) {
        // Sorting on descending height followed by ascending by k for same height
        Arrays.sort(people, (a, b) -> a[0] == b[0] ? a[1] - b[1] : b[0] - a[0]);
        ArrayList<int[]> list = new ArrayList<>();
        for (int[] x : people)
            list.add(x[1], x);
        return list.toArray(new int[people.length][]);
    }
}
```


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