> For the complete documentation index, see [llms.txt](https://mayanktyagi3111.gitbook.io/interview-prep/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://mayanktyagi3111.gitbook.io/interview-prep/dynamic-programming/untitled-8.md).

# Two City Scheduling

There are `2N` people a company is planning to interview. The cost of flying the `i`-th person to city `A` is `costs[i][0]`, and the cost of flying the `i`-th person to city `B` is `costs[i][1]`.

Return the minimum cost to fly every person to a city such that exactly `N` people arrive in each city.

**Example 1:**

```
Input: [[10,20],[30,200],[400,50],[30,20]]
Output: 110
Explanation: 
The first person goes to city A for a cost of 10.
The second person goes to city A for a cost of 30.
The third person goes to city B for a cost of 50.
The fourth person goes to city B for a cost of 20.

The total minimum cost is 10 + 30 + 50 + 20 = 110 to have half the people interviewing in each city.
```

**Note:**

1. `1 <= costs.length <= 100`
2. It is guaranteed that `costs.length` is even.
3. `1 <= costs[i][0], costs[i][1] <= 1000`

```java
class Solution {
    public int twoCitySchedCost(int[][] costs) {
        int sumToA = 0;
        int[] refund = new int[costs.length];
        for (int i = 0; i < costs.length; i++) {
            sumToA += costs[i][0];
            refund[i] = costs[i][1] - costs[i][0];
        }
        Arrays.sort(refund);

        for (int i = 0; i < refund.length / 2; i++)
            sumToA += refund[i];

        return sumToA;
    }
}
```


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