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# Non-overlapping Intervals

Given a collection of intervals, find the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping.

**Example 1:**

```
Input: [[1,2],[2,3],[3,4],[1,3]]
Output: 1
Explanation: [1,3] can be removed and the rest of intervals are non-overlapping.
```

**Example 2:**

```
Input: [[1,2],[1,2],[1,2]]
Output: 2
Explanation: You need to remove two [1,2] to make the rest of intervals non-overlapping.
```

**Example 3:**

```
Input: [[1,2],[2,3]]
Output: 0
Explanation: You don't need to remove any of the intervals since they're already non-overlapping.
```

**Note:**

1. You may assume the interval's end point is always bigger than its start point.
2. Intervals like \[1,2] and \[2,3] have borders "touching" but they don't overlap each other.

```java
class Solution {
    public int eraseOverlapIntervals(int[][] intervals) {
        if (intervals.length == 0)
            return 0;

        Arrays.sort(intervals, (a, b) -> a[1] - b[1]);
        int end = intervals[0][1];
        int count = 1;
        // Count total number of non overlapping intervals
        for (int i = 1; i < intervals.length; i++) {
            if (intervals[i][0] >= end) {
                end = intervals[i][1];
                count++;
            }
        }
        return intervals.length - count;
    }
}
```


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