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# Make Two Arrays Equal by Reversing Sub-arrays

Given two integer arrays of equal length `target` and `arr`.

In one step, you can select any **non-empty sub-array** of `arr` and reverse it. You are allowed to make any number of steps.

Return *True* if you can make `arr` equal to `target`, or *False* otherwise.

**Example 1:**

```
Input: target = [1,2,3,4], arr = [2,4,1,3]
Output: true
Explanation: You can follow the next steps to convert arr to target:
1- Reverse sub-array [2,4,1], arr becomes [1,4,2,3]
2- Reverse sub-array [4,2], arr becomes [1,2,4,3]
3- Reverse sub-array [4,3], arr becomes [1,2,3,4]
There are multiple ways to convert arr to target, this is not the only way to do so.
```

**Example 2:**

```
Input: target = [7], arr = [7]
Output: true
Explanation: arr is equal to target without any reverses.
```

**Example 3:**

```
Input: target = [1,12], arr = [12,1]
Output: true
```

**Example 4:**

```
Input: target = [3,7,9], arr = [3,7,11]
Output: false
Explanation: arr doesn't have value 9 and it can never be converted to target.
```

**Example 5:**

```
Input: target = [1,1,1,1,1], arr = [1,1,1,1,1]
Output: true
```

**Constraints:**

* `target.length == arr.length`
* `1 <= target.length <= 1000`
* `1 <= target[i] <= 1000`
* `1 <= arr[i] <= 1000`

```java
class Solution {
    public boolean canBeEqual(int[] target, int[] arr) {
        int n = arr.length;
        HashMap<Integer, Integer> map = new HashMap<>();
        for (int i = 0; i < n; i++)
            map.put(arr[i], map.getOrDefault(arr[i], 0) + 1);
        for (int i = 0; i < n; i++) {
            if (!map.containsKey(target[i]) || map.get(target[i]) == 0)
                return false;
            map.put(target[i], map.get(target[i]) - 1);
        }
        return true;
    }
}
```
