> For the complete documentation index, see [llms.txt](https://mayanktyagi3111.gitbook.io/interview-prep/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://mayanktyagi3111.gitbook.io/interview-prep/hashmap-and-hashset-and-sliding-window/minimum-window-substring.md).

# Minimum Window Substring

Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n).

**Example:**

```
Input: S = "ADOBECODEBANC", T = "ABC"
Output: "BANC"
```

**Note:**

* If there is no such window in S that covers all characters in T, return the empty string `""`.
* If there is such window, you are guaranteed that there will always be only one unique minimum window in S.

```java
class Solution {
    public String minWindow(String s, String t) {
        // Using array because this was faster than using HashMap
        int[] map = new int[128];
        for (char c : t.toCharArray())
            map[c]++;
        int start = 0, end = 0, minStart = 0, minLen = Integer.MAX_VALUE, counter = t.length();
        while (end < s.length()) {
            char c1 = s.charAt(end);
            if (map[c1] > 0)
                counter--;
            map[c1]--;
            while (counter == 0) {
                if (minLen > end - start + 1) {
                    minLen = end - start + 1;
                    minStart = start;
                }
                char c2 = s.charAt(start);
                map[c2]++;
                if (map[c2] > 0)
                    counter++;
                start++;
            }
            end++;
        }
        return minLen == Integer.MAX_VALUE ? "" : s.substring(minStart, minStart + minLen);
    }
}
```


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