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# Angle Between Hands of a Clock

Given two numbers, `hour` and `minutes`. Return the smaller angle (in degrees) formed between the `hour` and the `minute` hand.

**Example 1:**

<div align="center"><img src="https://assets.leetcode.com/uploads/2019/12/26/sample_1_1673.png" alt=""></div>

```
Input: hour = 12, minutes = 30
Output: 165
```

**Example 2:**

![](https://assets.leetcode.com/uploads/2019/12/26/sample_2_1673.png)

```
Input: hour = 3, minutes = 30
Output: 75
```

**Example 3:**

![](https://assets.leetcode.com/uploads/2019/12/26/sample_3_1673.png)

```
Input: hour = 3, minutes = 15
Output: 7.5
```

**Example 4:**

```
Input: hour = 4, minutes = 50
Output: 155
```

**Example 5:**

```
Input: hour = 12, minutes = 0
Output: 0
```

**Constraints:**

* `1 <= hour <= 12`
* `0 <= minutes <= 59`
* Answers within `10^-5` of the actual value will be accepted as correct.

```java
class Solution {
    public double angleClock(int hour, int minutes) {
        double min = minutes / 60.0;
        double h = (hour / 12.0) + (1.0 / 12.0) * (min);
        double diff = Math.abs(h - min);
        diff = Math.min(diff, 1.0 - diff);
        double angle = diff * 360;
        return angle;
    }
}
```


---

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