Given a string, find length of the longest repeating subseequence such that the two subsequence don’t have same string character at same position, i.e., any i’th character in the two subsequences shouldn’t have the same index in the original string.
Examples:
Input: str = "abc"
Output: 0
There is no repeating subsequence
Input: str = "aab"
Output: 1
The two subssequence are 'a'(first) and 'a'(second).
Note that 'b' cannot be considered as part of subsequence
as it would be at same index in both.
Input: str = "aabb"
Output: 2
Input: str = "axxxy"
Output: 2
classSolution {publicintlongestCommonSubsequence(String str) {int m =str.length();int dp[][] =newint[m +1][m +1];for (int i =0; i <= m; i++) {for (int j =0; j <= m; j++) {if (i ==0|| j ==0) dp[i][j] =0;elseif (str.charAt(i -1) ==str.charAt(j -1) && i != j) dp[i][j] =1+ dp[i -1][j -1];else dp[i][j] =Math.max(dp[i -1][j], dp[i][j -1]); } }return dp[m][m]; }}