Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST.
Basically, the deletion can be divided into two stages:
Search for a node to remove.
If the node is found, delete the node.
Note: Time complexity should be O(height of tree).
Example:
root = [5,3,6,2,4,null,7]
key = 3
5
/ \
3 6
/ \ \
2 4 7
Given key to delete is 3. So we find the node with value 3 and delete it.
One valid answer is [5,4,6,2,null,null,7], shown in the following BST.
5
/ \
4 6
/ \
2 7
Another valid answer is [5,2,6,null,4,null,7].
5
/ \
2 6
\ \
4 7
class Solution {
public TreeNode deleteNode(TreeNode root, int key) {
if (root == null)
return null;
if (root.val > key)
root.left = deleteNode(root.left, key);
else if (root.val < key)
root.right = deleteNode(root.right, key);
else {
if (root.left == null)
return root.right;
if (root.right == null)
return root.left;
TreeNode rightSmallest = root.right;
while (rightSmallest.left != null)
rightSmallest = rightSmallest.left;
rightSmallest.left = root.left;
return root.right;
}
return root;
}
}