On an 8x8 chessboard, there can be multiple Black Queens and one White King.
Given an array of integer coordinates queens that represents the positions of the Black Queens, and a pair of coordinates king that represent the position of the White King, return the coordinates of all the queens (in any order) that can attack the King.
Example 1:
Input: queens = [[0,1],[1,0],[4,0],[0,4],[3,3],[2,4]], king = [0,0]
Output: [[0,1],[1,0],[3,3]]
Explanation:
The queen at [0,1] can attack the king cause they're in the same row.
The queen at [1,0] can attack the king cause they're in the same column.
The queen at [3,3] can attack the king cause they're in the same diagnal.
The queen at [0,4] can't attack the king cause it's blocked by the queen at [0,1].
The queen at [4,0] can't attack the king cause it's blocked by the queen at [1,0].
The queen at [2,4] can't attack the king cause it's not in the same row/column/diagnal as the king.
Example 2:
Input: queens = [[0,0],[1,1],[2,2],[3,4],[3,5],[4,4],[4,5]], king = [3,3]
Output: [[2,2],[3,4],[4,4]]
Example 3:
Input: queens = [[5,6],[7,7],[2,1],[0,7],[1,6],[5,1],[3,7],[0,3],[4,0],[1,2],[6,3],[5,0],[0,4],[2,2],[1,1],[6,4],[5,4],[0,0],[2,6],[4,5],[5,2],[1,4],[7,5],[2,3],[0,5],[4,2],[1,0],[2,7],[0,1],[4,6],[6,1],[0,6],[4,3],[1,7]], king = [3,4]
Output: [[2,3],[1,4],[1,6],[3,7],[4,3],[5,4],[4,5]]
Constraints:
1 <= queens.length <= 63
queens[0].length == 2
0 <= queens[i][j] < 8
king.length == 2
0 <= king[0], king[1] < 8
At most one piece is allowed in a cell.
publicclassSolution {publicList<List<Integer>> queensAttacktheKing(int[][] queens,int[] king) {List<List<Integer>> result =newArrayList<>();boolean[][] seen =newboolean[8][8];for (int[] queen : queens) seen[queen[0]][queen[1]] =true;for (int dr =-1; dr <=1; dr++) { // find the nearest queen can attack king by 8 directionsfor (int dc =-1; dc <=1; dc++) {if (dr ==0&& dc ==0)continue; // exclude centerList<Integer> queen =findNearestQueenCanAttackKing(seen, king, dr, dc);if (queen !=null)result.add(queen); } }return result; }privateList<Integer> findNearestQueenCanAttackKing(boolean[][] seen,int[] king,int dr,int dc) {int r = king[0] + dr, c = king[1] + dc;while (r >=0&& c >=0&& r <8&& c <8) {if (seen[r][c])returnArrays.asList(r, c); r += dr; c += dc; }returnnull; }}