Maximum Length of Repeated Subarray
Given two integer arrays A
and B
, return the maximum length of an subarray that appears in both arrays.
Example 1:
Input:
A: [1,2,3,2,1]
B: [3,2,1,4,7]
Output: 3
Explanation:
The repeated subarray with maximum length is [3, 2, 1].
Note:
1 <= len(A), len(B) <= 1000
0 <= A[i], B[i] < 100
class Solution {
public int findLength(int[] A, int[] B) {
if (A == null || B == null)
return 0;
int m = A.length, n = B.length;
int max = 0;
// dp[i][j] is the length of longest common subarray
// ending with A[i] and B[j]
int[][] dp = new int[m + 1][n + 1];
for (int i = 0; i <= m; i++) {
for (int j = 0; j <= n; j++) {
// Base case
if (i == 0 || j == 0)
dp[i][j] = 0;
else {
if (A[i - 1] == B[j - 1]) {
dp[i][j] = 1 + dp[i - 1][j - 1];
max = Math.max(max, dp[i][j]);
}
}
}
}
return max;
}
}
Last updated