Compare Version Numbers
Compare two version numbers version1 and version2.
If version1 > version2 return 1,
If version1 < version2 return -1,
otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the .
character.
The .
character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5
is not "two and a half"
or "half way to version three"
, it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 1.13 < 1.13.4
import java.math.BigInteger;
public class Solution {
public int compareVersion(String A, String B) {
String[] s1 = A.split("\\.");
String[] s2 = B.split("\\.");
int i = 0;
while (i < s1.length || i < s2.length) {
BigInteger version1 = i < s1.length ? new BigInteger(s1[i]) : BigInteger.ZERO;
BigInteger version2 = i < s2.length ? new BigInteger(s2[i]) : BigInteger.ZERO;
int comparison = version1.compareTo(version2);
if (comparison != 0)
return comparison;
i++;
}
return 0;
}
}
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